Today I Learned 오늘 한 일 새로운 언어를 배우는 방법 
자료형 
연산자 
제어문, 반복문 
함수 
call by reference, call by value, call by object reference 
First class function인지 
 
 
Class 지원하는지 (
Encapsulation 
Inheritance 
Virtual function 지원 여부) 
 
 
 
Python Data Type과 기본 Data Structure 실습 Text 가위바위보 게임 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 import  randomdef  get_player_choice () :  """    get_player_choice() -> string   Return "바위" or "가위 or "보"   """   choice = input("가위바위보! : " )   while  choice != "가위"  and  choice != "바위"  and  choice != "보" :     choice = input("가위바위보! : " )   return  choice def  get_computer_choice () :  """    get_computer_choice -> string   Return "바위" or "가위 or "보"   """   tup = ("가위" , "바위" , "보" )   return  tup[random.randint(0 ,2 )] def  who_wins (player, computer) :  """    who_wins(player, com) -> string   Return if player wins 'player'   elif computer wins 'computer'   else None   """   if  player == computer:     return  None    if  (player == "바위"  and  computer == "가위" ) or \   (player == "가위"  and  computer == "보" ) or \   (player == "보"  and  computer == "바위" ):     return  'player'    else :     return  'computer'  def  play_one () :  """    play_one -> string   Return if player wins 'player'   elif computer wins 'computer'   """   player_win = 0    computer_win = 0    while  player_win == computer_win:     player = get_player_choice()     computer = get_computer_choice()     result = who_wins(player, computer)     print(f'Player {player}  vs Computer {computer} ' )     if  result == 'player' :       player_win += 1      elif  result == 'computer' :       computer_win += 1      if  player_win > computer_win:       return  'player'      else :       return  'computer'  def  check_final_winner (result) :  """    check_final_winner(result) -> string   result : ex) ['player', 'player']   Return if 'player' >= 2 in result, 'Player'   elif 'computer' >=2 in result, 'Computer'   else None   """   print(f"Player {result.count('player' )} 승 | Computer {result.count('computer' )}  승" )   if  result.count('player' ) >= 2 :     return  'Player'    else :     return  'Computer'  def  play () :  """    play() -> None   3판 2선승가위바위보   """   result_list = []   for  i in  range(3 ):     result_list.insert(i, play_one())   print(check_final_winner(result_list)+" Wins!!" ) if  __name__=="__main__" :  play() 
 
ASCII와 UNICODE ASCII와 UNOCODE의 역사, UNICODE의 Encoding, Decoding 방법도 배웠다.
Python Bubble Sort 1 2 3 4 5 6 7 8 9 10 11 def  bubble_sort (li) :  n = len(li)   for  i in  range(n-1 ):     for  j in  range(n-1 -i):       if  li[j] > li[j+1 ]:         li[j], li[j+1 ] = li[j+1 ], li[j] if  __name__ == "__main__" :  li=[6 , 2 , 1 , 4 ]   bubble_sort(li)   print(li) 
 
간단한 Bubble Sort function을 만들었다.
알고리즘 CodeWars 6kyu. Persistent Bugger 
그리고 LeetCode의 Medium Level 문제를 풀려고 했는데 Dynamic Programming 개념이 들어가 쉽지 않다. 주말 내내 풀어야겠다.